50(1+(4/12))^120=x

Solution for 50(1+(4/12))^120=x equation:

50(1+(4/12))^120=x

We move all terms to the left:

50(1+(4/12))^120-(x)=0

We add all the numbers together, and all the variables

-x+50(1+(+4/12))^120=0

We add all the numbers together, and all the variables

-1x+50(1+(+4/12))^120=0

We multiply all the terms by the denominator


-1x*12))^120+50(1+(+4=0

Wy multiply elements

-12x^2+4=0

a = -12; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-12)·4
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*-12}=\frac{0-8\sqrt{3}}{-24}
=-\frac{8\sqrt{3}}{-24}
=-\frac{\sqrt{3}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*-12}=\frac{0+8\sqrt{3}}{-24}
=\frac{8\sqrt{3}}{-24}
=\frac{\sqrt{3}}{-3}
$